Mookie Betts, Christian Yelich win MVP awards

Christian Yelich

The MVPs this season are both first-time winners, and neither of them is a surprise: outfielder Mookie Betts of the Boston Red Sox in the AL and outfielder Christian Yelich of the Milwaukee Brewers in the NL.

At the halfway point of the season, Yelich was not the front-runner for the award. But from July 8 on, he hit .367 with a .444 on-base percentage. His .770 slugging percentage after the All-Star Game was baseball's best in 14 years, and over 74 games, he totaled 25 home runs, 22 doubles and a 1.171 OPS.

The Brewers overtook the Cubs in the NL Central in a Game 163 and finished with a league-best 96 wins. Obviously, they do not accomplish that without Yelich's red-hot second half.

Yelich won the batting title with a .326 average. He finished tied for third in the league with 36 home runs, and his 110 RBIs ranked second.

Really, he was darn close to a Triple Crown, which made this vote obvious.

Yelich earned 29 of the 30 first-place votes -- the other went to New York Mets pitcher Jacob deGrom. The Cubs' Javier Baez had 19 second-place votes and finished second. Colorado's Nolan Arenado, who led the NL with 38 home runs, placed third.

As for Betts, he became the first player in MLB history to win a batting title in the same season in which he also had at least 30 home runs and 30 stolen bases. The right fielder's slash line was .346/.438/.640, and simply put, he was the best player on the best team -- the 108-win and World Series champion Red Sox.

Betts finished with 47 doubles, 32 home runs, 129 runs scored and 30 stolen bases. He's also the best defensive right fielder in the game, earning his third consecutive Gold Glove at the position this season.

Twenty-eight of the 30 first-place votes went to Betts. Runner-up Mike Trout appeared first on one ballot, and he got 24 second-place votes. Cleveland infielder Jose Ramirez placed third.